Thu gọn:
\(B=\left(x-3\right)\left(x+3\right)\left(x^2+9\right)-\left(x^2+2\right)\left(x^2-2\right)\)
\(T=\left(x-5\right)\left(x+2\right)+3.\left(x-2\right)\left(x+2\right)-\left(3x-\frac{1}{2}\right)^2+5x^2\)
\(Q=\left(x-2\right)^3+6\left(x-1\right)^2-\left(x+1\right)\left(x^2-x+1\right)\)
Làm đc cái nào thì làm, ko bắt m.n làm cả đâu ! Làm đc hết thì mk cảm ơn!
Trả lời:
\(B=\left(x-3\right).\left(x+3\right).\left(x^2+9\right)-\left(x^2+2\right).\left(x^2-2\right)\)
\(B=\left(x^2-9\right).\left(x^2+9\right)-\left(x^4-4\right)\)
\(B=\left(x^4-81\right)-\left(x^4-4\right)\)
\(B=x^4-81-x^4+4\)
\(B=-77\)
@huynip123, dễ thì a làm hộ e đi !
M trả lời tiếp câu T, Q nhé
\(T=\left(x-5\right).\left(x+2\right)+3.\left(x-2\right).\left(x+2\right)-\left(3x-\frac{1}{2}\right)^2+5x^2\)
\(T=\left(x+2\right).\left(x-5+3x-6\right)-\left(9x^2-3x+\frac{1}{4}\right)+5x^2\)
\(T=\left(x+2\right).\left(4x-11\right)-9x^2+3x-\frac{1}{4}+5x^2\)
\(T=4x^2-11x+8x-22-9x^2+3x-\frac{1}{4}+5x^2\)
\(T=\frac{-89}{4}\)
\(Q=\left(x-2\right)^3+6.\left(x-1\right)^2-\left(x+1\right).\left(x^2-x+1\right)\)
\(Q=x^3-6x^2+12x-8+6.\left(x^2-2x+1\right)-\left(x^3+1\right)\)
\(Q=x^3-6x^2+12x-8+6x^2-12x+6-x^3-1\)
\(Q=-3\)
Học tốt
@nguyenhainama7: Cảm ơn a nhiều ạ !
