Bài làm
\(a\left(b-c-d\right)-b\left(c+a\right)=ab-ac-ad-bc-ba\)
\(=-ac-ad-bc\)
a ( b - c - d ) - b ( c + a )
=a.b-a.c-a.d-b.c-b.a
= -a.c-c.d-b.c
\(a\left(b-c-d\right)-b\left(c+a\right)\)
\(=ab-ac-ad-bc-ba\)
\(=\left(ab-ba\right)-ac-ad-bc\)
\(=-ac-ad-bc\)
Học tốt
a( b - c - d ) - b( c + a )
= ab - ac - ad - bc + ab
= -ac - ad - bc
\(a.\left(b-c-d\right)-b.\left(c+a\right)\)
\(=ab-ac-ad-bc-ba\)
\(=-ac-ad-bc\)
a ( b - c - d ) - b ( c + a ) = ( ab - ac - ad ) - ( bc + ba )
= ab - ac - ad - bc - ba
= ( ab - ba ) - ac - ad - bc
= -ac - ad - bc