abc+ ab = bccb= 910+91=1001
abc + ab = bccb
a x 100 + bx10 + c + a x10 + b = b x 1000 + cx100+ cx10 + b
a x 110 – b x 990 = c x 109
110 x ( a – b x 9 ) = c x 109
a = 9, b = 1, c = 0. Vậy abc = 910
abc + ab = bccb
a x 100 + bx10 + c + a x10 + b = b x 1000 + cx100+ cx10 + b
a x 110 – b x 990 = c x 109
110 x ( a – b x 9 ) = c x 109
a = 9, b = 1, c = 0. Vậy abc = 910
abc+ab=bccb
100a+10b+c+10a+b=1000b+100c+10c+b
100a+10a+10b+b+c=1000b+b+110c
110a+11b+c=1001b+110c
110a+11b+c-110c=1001b
110(a-c)=1001b-11b
110(a-c)=990b
a-c=9b
Ta có 0<a-c<10
Mà a-c=9b
a-c=0=9b hoặc a-c=9=9b
a-c=0=b
