Question

\(\text{3x+1-3x-2-3x=2}\frac{8}{9}\)

Answer 1

\(3x+1-3x-2-3x=2\frac{8}{9}\)

=>\(1-2-3x=2\frac{8}{9}\)

=>\(-1-3x=\frac{26}{9}\)

=>\(3x=-1-\frac{26}{6}\)

=>\(3x=-\frac{35}{9}\)

=>\(x=\left(-\frac{35}{9}\right):3\)

=>\(x=-\frac{35}{27}\)

Answer 2

\(3^{x+1}-3^{x-2}3^x=2\frac{8}{9}\)

Answer 3

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