|(x-2)(x+5)|=0
=> (x-2)(x+5)=0
=> x - 2 = 0
x = 0 + 2
x= 2
x + 5 = 0
x = 0 - 5
x = -5
Vậy x \(\in\) { 2 ; -5 }
|(x-2)(x+5)|=0
=> (x-2)(x+5)=0
=> x-2=0 => x=0+2=2
x+5=0 => x=0-5=-5
Vậy x\(\in\){-5;2}
Ne nhung so nao nhan 0 cha =0 Vay neu x -2 = 1 con x +5 = 0 thi / ( x - 2 ) ( x + 5 ) / = 0
suy ra x = 3 hoac x = -5
Con rat nhieu trong hop nua