Question

Tập hợp các số nguyên x sao cho: (x^2+7x+2) chia hết (x+7).

Answer 1

\(\left(x^2+7x+2\right):\left(x+7\right)\)

\(\Rightarrow\left(x^2+7x+2\right)-x.\left(x+7\right):\left(x+7\right)\)

\(\Rightarrow x^2+7x+2-x^2-7x:\left(x+7\right)\)

\(\Rightarrow2:x+7\Rightarrow x+7\inƯ\left(2\right)=\left\{2;1;-2;-1\right\}\)

\(\Rightarrow x\in\left\{-5;-6;-9;-8\right\}\)