Ta có:
15-|x-2|=12
|x-2|=15-12
|x-2|=3
=> x-2 \(\in\){-3;3}
Với x-2= -3
x = -3+2
x = -1
Với x-2 = 3
x = 3+2
x = 5
Vậy x\(\in\){-1;5} thì 15-|x-2|=12
=> /x-2/=15-12
=> /x-2/=3
=> x-2={-3;3}
Nếu x-2=3 thì x=5
Nếu x-2=-3 thì x= -1
Ta có:
15-|x-2|=12
|x-2|=15-12
|x-2|=3
=> x-2 \(\in\){-3;3}
Với x-2= -3
x = -3+2
x = -1
Với x-2 = 3
x = 3+2
x = 5
Vậy x\(\in\){-1;5} thì 15-|x-2|=12
=> /x-2/=15-12
=> /x-2/=3
=> x-2={-3;3}
Nếu x-2=3 thì x=5
Nếu x-2=-3 thì x= -1
tap hop cac so nguyen x thoa man 15-|x-2|=12
Tim tap hop cac so nguyen x sao cho-6<x5 hay tinh tong cac so nguyen trong tap hop do
tap hop cac so nguyen x thoa man 15-/x-2\=12 la
tap hop cac so nguyen x thoa man -2 ^.Ix+1I=-2^6 la
so phan tu cua tap hop cac so nguyen x thoa man:15-lx-2l bang 12
so nguyen la gi .neu x la so nguyen thi x thuoc tap hop Z kohay tap hop z la tap hop cac so nguyen à
tap hop cac so nguyen to x sao cho 6 chia het cho (x-1)
tap hop cac so nguyen x thoa man -3 x |2x - 3 |= -12
tim giao cua 2 tap hop A va B biet rang:
a , A la tap hop cac so chia het cho 24 , B la tap hop cac so chia het cho 120
b, A la tap hop cac so chan, B la tap hop cac so nguyen to