\(\sqrt{x-2011}+\sqrt{4x-8044}=3\)
\(\Leftrightarrow\sqrt{x-2011}+2\sqrt{x-2011}=3\)
\(\Leftrightarrow3\sqrt{x-2011}=3\Leftrightarrow\sqrt{x-2011}=1\)
\(\Leftrightarrow x-2011=1\Leftrightarrow x=2012\left(tm\right)\)
Vậy pt có nghiệm x = 2012
Giải:
\(\sqrt{x-2011}+\sqrt{4x-8044}=3\)
\(\Leftrightarrow\sqrt{x-2011}+4\sqrt{x-2011}=3\)
\(\Leftrightarrow\left(\sqrt{x-2011}\right)\left(1+4\right)=3\)
\(\Leftrightarrow5\sqrt{x-2011}=3\)
\(\Leftrightarrow\sqrt{x-2011}=\dfrac{3}{5}\)
\(\Leftrightarrow\left(\sqrt{x-2011}\right)^2=\left(\dfrac{3}{5}\right)^2\)
\(\Leftrightarrow x-2011=\dfrac{9}{25}\)
\(\Leftrightarrow x=\dfrac{50284}{25}=2011,36\)
Vậy ...
P/s: Chắc sai từ dòng đầu tiên :)