\(\frac{2x-3}{x-1}=4\)
2x-3=4x-4
-2x=1
x=-1/2
\(\sqrt{\frac{2x-3}{x-1}}=2\)
Bình phương 2 vế, ta được:
\(\left(\sqrt{\frac{2x-3}{x-1}}\right)^2=2^2\)
\(\Leftrightarrow\frac{2x-3}{x-1}=4\)
\(\Leftrightarrow2x-3=\left(x-1\right).4\)
\(\Leftrightarrow2x-3=4x-4\)
\(\Leftrightarrow2x=1\)
\(\Leftrightarrow x=\frac{1}{2}\)
(Nhớ k cho mình với nhoa!)