Các câu hỏi tương tự
Tìm abcd,biết
a=\(\sqrt{49}\)
\(\sqrt{25}\)=b
c=8765433456780-1
d=8-8+8
tìm đc abcd tìm ra dụ ý của bài(ý nghĩa của dãy số)
sqrt{4+sqrt{6}}..........sqrt{4+sqrt{6}}..........sqrt{4+sqrt{6}}..........sqrt{4+sqrt{6}}..........sqrt{4+sqrt{6}}..........sqrt{4+sqrt{6}}..........sqrt{4+sqrt{6}}..........sqrt{4+sqrt{6}}..........sqrt{4+sqrt{6}}..........sqrt{4+sqrt{6}}..........
Đọc tiếp
\(\sqrt{4+\sqrt{6}}=..........\)
\(\sqrt{4+\sqrt{6}}=..........\)
\(\sqrt{4+\sqrt{6}}=..........\)
\(\sqrt{4+\sqrt{6}}=..........\)
\(\sqrt{4+\sqrt{6}}=..........\)
\(\sqrt{4+\sqrt{6}}=..........\)
\(\sqrt{4+\sqrt{6}}=..........\)
\(\sqrt{4+\sqrt{6}}=..........\)
\(\sqrt{4+\sqrt{6}}=..........\)
\(\sqrt{4+\sqrt{6}}=..........\)
A(frac{left(sqrt{x}-1right)left(x+sqrt{x}+1right)}{sqrt{x}left(sqrt{x}-1right)}-frac{left(sqrt{x}+1right)left(x-sqrt{x}+1right)}{sqrt{x}left(sqrt{x}+1right)}):(frac{2left(sqrt{x}-1right)^2}{x-1}left(frac{x+sqrt{x}+1-left(x-sqrt{x}+1right)}{sqrt{x}}right).frac{sqrt{x}+1}{2left(sqrt{x}-1right)}frac{2sqrt{x}}{sqrt{x}}.frac{sqrt{x}+1}{2left(sqrt{x}-1right)}frac{sqrt{x}+1}{sqrt{x}-1}
Đọc tiếp
A=(\(\frac{\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)}{\sqrt{x}\left(\sqrt{x}-1\right)}\)-\(\frac{\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}{\sqrt{x}\left(\sqrt{x}+1\right)}\)):(\(\frac{2\left(\sqrt{x}-1\right)^2}{x-1}\)
=\(\left(\frac{x+\sqrt{x}+1-\left(x-\sqrt{x}+1\right)}{\sqrt{x}}\right).\frac{\sqrt{x}+1}{2\left(\sqrt{x}-1\right)}\)
=\(\frac{2\sqrt{x}}{\sqrt{x}}.\frac{\sqrt{x}+1}{2\left(\sqrt{x}-1\right)}\)=\(\frac{\sqrt{x}+1}{\sqrt{x}-1}\)
\(y=\frac{1}{x^2+\sqrt{x}}\sqrt[]{}\sqrt{\sqrt[]{}\sqrt[]{}\frac{\frac{\frac{\frac{ }{ }}{ }}{ }}{ }}\)
1+4+9+16+25+36+49+64+81+100=?
1/5+4/10+9/15+25/25+36/30+49/35+64/40+81/45
1/5+4/10+9/15+16/20+25/25+36/30+49/35+64/60+81/45
6 tháng 4 2021 lúc 21:09
tính nhanh :
1/5+4/10+9/15+16/20+25/25+36/30+49/35+64/40+81/45
cần gấp mn !!!
1/5+4/10+9/15+16/20+25/25+36/30+49/35+64/40+81/45