C=1/2.(3/60.63+....+3/117.120)+1/1003
C=1/2.(1/60-1/63+....+1/117-1/120)+1/1003
....còn lại tự làm nha, bài còn lại cũng tương tự
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So sánh \(A=\frac{2}{60.63}+\frac{2}{63.66}+...+\frac{2}{117.120}+\frac{2}{2006}\)và \(B=\frac{5}{40.44}+\frac{5}{44.48}+...+\frac{5}{76.80}+\frac{5}{2006}\)
So sánh
A=\(\frac{2}{60.63}+\frac{2}{63.66}+...+\frac{2}{117.120}+\frac{2}{2003}\)
và B=\(\frac{5}{40.44}+\frac{5}{44.48}+...+\frac{5}{76.80}+\frac{5}{2003}\)
So sánh
A=\(\frac{2}{60.63}+\frac{2}{63.66}+...+\frac{2}{117.120}+\frac{2}{2003}\)
và B=\(\frac{5}{40.44}+\frac{5}{44.48}+...+\frac{5}{76.80}+\frac{5}{2003}\)
So sánh
A=\(\frac{2}{60.63}+\frac{2}{63.66}+..+\frac{2}{117.120}+\frac{2}{2003}\)
B=\(\frac{5}{40.44}+\frac{5}{44.48}+..+\frac{5}{76.80}+\frac{5}{2003}\)
so sánh
A=\(\frac{2}{60.63}+\frac{2}{63.66}+......+\frac{2}{117.120}+\frac{2}{2017}\)
B=\(\frac{5}{40.44}+\frac{5}{44.48}+........+\frac{5}{76.80}+\frac{5}{2017}\)
17 tháng 8 2021 lúc 15:39
So sánh:
\(A=\dfrac{2}{60.63}+\dfrac{2}{63.66}+.........+\dfrac{2}{117.120}+\dfrac{2}{2003}\)
và \(B=\dfrac{5}{40.44}+\dfrac{5}{44.48}+........+\dfrac{5}{76.08}+\dfrac{5}{2003}\)
So sánh:
A= 2/60.63+2/63.66+....+2/117.120+2/2003
B=5/40.44+5/44.48+...+5/76.80+5/2003
Làm hộ mình nha !
Tìm x
a/\(\frac{x+7}{2003}+\frac{x+4}{2006}=\frac{x-1}{2011}+\frac{x-5}{2015}\)
b/\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
c/\(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
Tính:
\(A=\frac{3^3+1^3}{2^3-1^3}+\frac{5^3+2^3}{3^3-2^3}+..............+\frac{4013^3+2006^3}{2007^3-2006^3}\)