Vì A < 1
\(\Rightarrow A< \frac{2017^{2018}+1+2016}{2017^{2019}+1+2016}=\frac{2017^{2018}+2017}{2017^{2019}+2017}=\frac{2017\left(2017^{2017}+1\right)}{2017\left(2017^{2018}+1\right)}=\frac{2017^{2017}+1}{2017^{2018}+1}=B\)
Vậy A < B
So sánh
A=\(\frac{2017^{2017}+1}{2017^{2018}+1}\)
\(B=\frac{2017^{2018}+1}{2017^{2019}+1}\)
So sánh:
\(C=\frac{2018^{2019}-1}{2018^{2018}-1}\)và\(D=\frac{2017^{2018}+1}{2017^{2017}+1}\)
So sánh: \(\frac{2017}{2018+2019}\)+ \(\frac{2018}{2017+2019}\)+ \(\frac{2019}{2017+2018}\)và 1
Bạn nào làm đúng mình tik cho
so sánh A=\(\frac{2016^{2017}+1}{2017^{2018}+1}\)và B=\(\frac{2017^{2018}+1}{2017^{2017}+1}\)
So sánh : A=\(\frac{2017^{2016}+1}{2017^{2017}+1}\) B=\(\frac{2017^{2017}+1}{2017^{2018}+1}\)
Cho A= \(\frac{2017^{2018}+1}{2017^{2018}-3}\)
B= \(\frac{2017^{2018}-1}{2017^{2018}-5}\)
Hãy so sánh A với B
so sánh A và B
A = \(\frac{2015}{2016}-\frac{2016}{2017}+\frac{2017}{2018}-\frac{2018}{2019}\)
B=\(\frac{-1}{2015.2016}-\frac{1}{2017.2018}\)
Cho
A = \(\frac{2017^{2018}+1}{2017^{2018}-3}\)
B= \(\frac{2017^{2018}-1}{2017^{2018}-5}\)
So sánh A và B
\(A=\frac{2019^{2018}+1}{2019^{2017}+1}\) \(B=\frac{2019^{2017}+1}{2018+1}\)
So sánh hai phân số
