A = \(\frac{976}{987}\) + \(\frac{987}{988}\) = \(1,987842971\)
B = \(\frac{986+987}{987+988}\)= \(\frac{1973}{1975}\) = \(0,9989873418\)
Mà \(1,987842971\)> \(0,9989873418\)
Nên: A > B
Ta có: \(\frac{986}{987}>\frac{986}{987+988}\)
\(\frac{987}{988}>\frac{987}{987+988}\)
\(\Rightarrow\frac{976}{987}+\frac{987}{988}>\frac{986+987}{987+988}\)
=> A > B