Các câu hỏi tương tự
So sánh:
a, \(A=\frac{252\cdot386-134}{252+386\cdot251}\) và \(B=\frac{212315\cdot653247-440932}{212314\cdot653247-212315}\)
b,\(A=\frac{2^{2007}+3}{2^{2006}+3}\) và \(B=\frac{2^{2004}+1}{2^{2003}+1}\)
Bài 1:So Sánh:200920và 2009200910
Bài 2:Tính tỉ số \(\frac{A}{B}\), biết:
\(A=\frac{1}{2}\)+\(\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2007}+\frac{1}{2008}+\frac{1}{2009}\)
\(B=\frac{2008}{1}+\frac{2007}{2}+\frac{2006}{3}+...+\frac{2}{2007}+\frac{1}{2008}\)
So sánh
\(A=\frac{2^{2008}-3}{2^{2007}-1}\) và \(B=\frac{2^{2007}-3}{2^{2006}-1}\)
So sánh\(A=\frac{2^{2006}+7}{2^{2004}+7}\)và\(B=\frac{2^{2003}+1}{2^{2001}+1}\)
A A > B
B A = B
C A < B
1.\(A=\frac{a}{b+c}=\frac{c}{a+b}=\frac{b}{c+a}\)
2. \(B=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+\frac{1}{4}\left(1+2+3+4\right)+...+\frac{1}{20}\left(1+2+3+...+20\right)\)
3. Hãy so sánh A và B
\(A=\frac{10^{2006}+1}{10^{2007}+1}\) \(B=\frac{10^{2007}+1}{10^{2008}+2}\)
Tính giá trị biểu thức:
A= \(\frac{\text{(a+1)(a+2)(a+3)....(a+2003)(a+2004) }}{(b+5)(b+6)(b+7)....(b+2006)(b+2007)}\) tại a= 0, b= -4
B= \(\frac{1}{\text{(x−5)(y+7) }}+\frac{1}{(x−4)(y+8)}+....+\frac{1}{(x−1)(y+11)}\)tại x= 6, y= -5
Cho Afrac{frac{1}{1.101}+frac{1}{2.102}+frac{1}{3.103}+...+frac{1}{25.125}}{frac{1}{1.26}+frac{1}{2.27}+frac{1}{3.28}+...+frac{1}{100.125}}. . Bfrac{frac{16}{9}-frac{16}{127}+frac{16}{2017}}{frac{5}{2017}+frac{5}{9}-frac{5}{127}}-frac{frac{6000}{43}-frac{6000}{257}-frac{125}{42}}{frac{2000}{43}-frac{250}{252}-frac{2000}{257}}.Chứng minh rằng Afrac{1}{2007^2}+frac{1}{2006^2}+frac{1}{2005^2}+...+frac{1}{7^2}+frac{1}{6^2}+frac{1}{5^2}B.
Đọc tiếp
Cho \(A=\frac{\frac{1}{1.101}+\frac{1}{2.102}+\frac{1}{3.103}+...+\frac{1}{25.125}}{\frac{1}{1.26}+\frac{1}{2.27}+\frac{1}{3.28}+...+\frac{1}{100.125}}.\) .
\(B=\frac{\frac{16}{9}-\frac{16}{127}+\frac{16}{2017}}{\frac{5}{2017}+\frac{5}{9}-\frac{5}{127}}-\frac{\frac{6000}{43}-\frac{6000}{257}-\frac{125}{42}}{\frac{2000}{43}-\frac{250}{252}-\frac{2000}{257}}.\)
Chứng minh rằng \(A>\frac{1}{2007^2}+\frac{1}{2006^2}+\frac{1}{2005^2}+...+\frac{1}{7^2}+\frac{1}{6^2}+\frac{1}{5^2}>B.\)
Tính tỉ số \(\frac{A}{B}\)biết
\(A=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2007}+\frac{1}{2008}+\frac{1}{2009}\)
\(B=\frac{2008}{1}+\frac{2007}{2}+\frac{2006}{3}+..+\frac{2}{2007}+\frac{1}{2008}\)
Tính tỉ số \(\frac{A}{B}\)biết :
\(A=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2009}\)
\(B=\frac{2008}{1}+\frac{2007}{2}+\frac{2006}{3}+...+\frac{2}{2007}+\frac{1}{2008}\)