Ta thấy :
\(\frac{20}{39}>\frac{14}{39}\)
\(\frac{22}{27}>\frac{22}{29}\)
\(\frac{18}{43}< \frac{18}{41}\)
\(\Rightarrow\frac{20}{39}+\frac{22}{27}+\frac{18}{43}>\frac{14}{39}+\frac{22}{29}+\frac{18}{41}\)
=> A > B
so sánh \(A=\frac{20}{39}+\frac{22}{27}+\frac{18}{43};B=\frac{14}{39}+\frac{22}{29}+\frac{18}{41}\)
so sánh A và B
A=\(\frac{20}{39}\)+\(\frac{22}{27}\)+\(\frac{18}{43}\)
B=\(\frac{14}{39}\)+\(\frac{22}{29}\)+\(\frac{18}{41}\)
1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 * 9 * 10 * 11 * 12 * 13 * 14 * 15 * 16 * 17 * 18 * 19 * 20 * 21 * 22 * 23 * 24 * 25 * 26 * 27 * 28 * 29 * 30 * 31 * 32 * 33 * 34 * 35 * 36 * 37 * 38 * 39 * 40 * 41 * 42 * 43 * 44 * 45 * 46 * 47 * 48 * 49 * 50 * 51 * 52 * 53 * 54 * 55 * 56 * 57 * 58 * 59 * 60 * 61 * 62 * 63 * 64 * 65 * 66 * 67 * 68 * 69 * 70 * 71 * 72 * 73 * 74 * 75 * 76 * 77 * 78 * 79 * 80 * 81 * 82 * 83 * 84 * 85 * 86 * 87 * 88 * 89 * 90 * 91 * 92 * 93 * 94 * 95 * 96 * 97 * 98 * 99 * 100 bằng bao nhiêu?
tim x
a,\(\left(x-20\right)+\left(x-19\right)+\left(x-18\right)+....+200+201=201\)
b, \(\frac{x+1}{1}+\frac{2x+3}{3}+\frac{3x+5}{5}+....+\frac{20x+39}{39}=22+\frac{4}{3}+\frac{6}{5}+...+\frac{40}{39}\)
1)So sánh 2 lũy thừa: 18^39 và 2^156
2)(-32)^27 và (-18)^39
So sánh
a) \(\frac{17}{30}\)và \(\frac{51}{92}\)
b) \(\frac{-45}{47}\)và \(\frac{31}{-30}\)
c) \(\frac{22}{67}\)và \(\frac{51}{152}\)
d) \(-\frac{17}{39};\frac{18}{-39}\)và \(-\frac{17}{41}\)
tinh tong: 2+4-6-8+10+12-14-16+18+20-22-24...-2008
a) – (- 18 + 45) – (18 + 55)
b) 24. (5 – 178) + 178 . (10 + 24)
c) 29 . ( - 101)
d) (- 56 + 130) – (43 – 56) – (- 20 – 43)
giúp mik vs ạ
{(-5/7)-7/9+9/11-11/13}x(3-3/4)
(10/21+14/27-6/11+22/39):(2-2/3)
