\(\frac{10^8+2}{10^8-1}=\frac{10^8-1+3}{10^8-1}=1+\frac{3}{10^8-1}\)
\(\frac{10^8}{10^8-3}=\frac{10^8-3+3}{10^8-3}=1+\frac{3}{10^8-3}\)
Ta có: \(\frac{3}{10^8-1}< \frac{3}{10^8-3}\)
\(\Rightarrow1+\frac{3}{10^8-1}< 1+\frac{3}{10^8-3}\)
\(\Rightarrow\frac{10^8+2}{10^8-1}< \frac{10^8}{10^8-3}\)
Ta có:\(\frac{196}{197}+\frac{197}{198}=\left(1-\frac{1}{197}\right)+\left(1-\frac{1}{198}\right)=2-\frac{1}{197}-\frac{1}{198}>2-1=1\)
Mà \(\frac{196+197}{197+198}< \frac{197+198}{197+198}=1\)
\(\Rightarrow\frac{196}{197}+\frac{197}{198}>\frac{196+197}{197+198}\)
c) tương tự câu a
Tham khảo nhé~