\(3\sqrt{2}\approx4,2426...\)
\(2\sqrt{5}\approx4,4721\)
Ta có: \(4,2426< 4,4721\)
\(\Rightarrow3\sqrt{2}< 2\sqrt{5}\)
ta có\(3\sqrt{2}=\sqrt{3^2\times2}=\)\(\sqrt{18}\)
ta có \(2\sqrt{5}=\sqrt{2^2\times5}=\)\(\sqrt{20}\)
ta thấy \(20>18\Rightarrow\sqrt{20}>\sqrt{18}\)hay \(2\sqrt{5}>3\sqrt{2}\)