ta có:21/52=210/520=1-(310/520)
213/523=1-(310/523)
vì 1-(310/520)<1-(310/523)
suy ra:21/52<213/523
vậy 21/52<231/523
ta có:21/52=210/520=1-(310/520)
213/523=1-(310/523)
vì 1-(310/520)<1-(310/523)
suy ra:21/52<213/523
vậy 21/52<231/523
ta có:21/52=210/520=1-(310/520)
213/523=1-(310/523)
vì 1-(310/520)<1-(310/523)
suy ra:21/52<213/523
vậy 21/52<231/523
ta có:21/52=210/520=1-(310/520)
213/523=1-(310/523)
vì 1-(310/520)<1-(310/523)
suy ra:21/52<213/523
vậy 21/52<231/523
ta có:21/52=210/520=1-(310/520)
213/523=1-(310/523)
vì 1-(310/520)<1-(310/523)
suy ra:21/52<213/523
vậy 21/52<231/523
ta có:21/52=210/520=1-(310/520)
213/523=1-(310/523)
vì 1-(310/520)<1-(310/523)
suy ra:21/52<213/523
vậy 21/52<231/523
ta có:21/52=210/520=1-(310/520)
213/523=1-(310/523)
vì 1-(310/520)<1-(310/523)
suy ra:21/52<213/523
vậy 21/52<231/523
Ta có : 21/52 = 210/520 = 1 - ( 310/520 )
213/523 =1 - ( 310/523 )
Vì 1 - ( 310/520 ) < 1 - ( 310/523 )
Vậy 21/52 < 231/523
Đ / S : <
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xin giải lại
Ta có :
\(\frac{21}{52}=\frac{210}{520}=1-\frac{310}{520}\)
\(\frac{213}{523}=1-\frac{310}{523}\)
Vì \(1-\frac{310}{520}>1-\frac{310}{523}\)nên \(\frac{21}{52}>\frac{213}{523}\)
Vậy \(\frac{21}{52}>\frac{213}{523}\)
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