Question

so sánh :

x=2020/2019 và y=2021/2020

lm giúp tui nhanh vs m.n

Answer 1

x > y

'-'

Answer 2

Có \(x=\frac{2020}{2019}\) và \(y=\frac{2021}{2020}\). Xét phần hơn

Có \(x-1=\frac{2020}{2019}-1=\frac{2020}{2019}-\frac{2019}{2019}=\frac{1}{2019}\)

Có \(y-1=\frac{2021}{2020}-1=\frac{2021}{2020}-\frac{2020}{2020}=\frac{1}{2020}\)

Vì \(\frac{1}{2019}>\frac{1}{2020}\Leftrightarrow\frac{2020}{2019}>\frac{2021}{2020}\Rightarrow x>y\)

Answer 3

\(1-\frac{2020}{2019}=-\frac{1}{2019}\)

\(1-\frac{2021}{2020}=-\frac{1}{2020}\)

\(-\frac{1}{2019}< -\frac{1}{2020}\Rightarrow1-\frac{2020}{2019}< 1-\frac{2021}{2020}\)

Trừ cả hai vế cho 1

\(\Rightarrow-\frac{2020}{2019}< -\frac{2021}{2020}\)

\(\Rightarrow\frac{2020}{2019}>\frac{2021}{2020}\)

Answer 4

lm chi tiết giùm cái

Answer 5

x=2020/2019=2019+1/2019=2019/2019+1/2019=1+1/2019

y=2021/2020=2020+1/2020=2020/2020+1/2020=1+1/2020

Vì 2019<2020

=>1+1/2019>1+1/2020

=>x>y

Vầy ms đúng nek m.n

Answer 6

Ta có : \(x=\frac{2020}{2019}=1+\frac{1}{2019}\)

\(y=\frac{2021}{2020}=1+\frac{1}{2020}\)

mà \(\frac{1}{2019}>\frac{1}{2020}\Rightarrow1+\frac{1}{2019}>1+\frac{1}{2020}\)

\(\Rightarrow\frac{2020}{2019}>\frac{2021}{2020}\)

hay \(x>y\)

Answer 7

m.n lm đều đúng 

greninja lm hơi tắt nha