\(\frac{1234\times1235-1}{1234\times1235}=1-\frac{1}{1234\times1235};\frac{1235\times1236-1}{1235\times1236}=1-\frac{1}{1235\times1236}=1-\frac{1}{1235\times1234+1235\times2}\)
Vì 1234*1235 < 1235*1234+1235*2 nên \(\frac{1}{1234\times1235}>\frac{1}{1235\times1234+1235\times2}\).
Do đó \(1-\frac{1}{1234\times1235}
\(\frac{1234\times1235-1}{1234\times1235}\&\frac{1235\times1236-1}{1235\times1236}\)
Đề vậy hả