Cho M= 2017/1.2 + 2017/2.3 + 2017/3.4 +.....+ 2017/99.100
P= 2018/51 + 2018/52 + 2018/53 +.........+ 2018/100
So Sánh M với P
so sánh 2 số A và B nếu
\(A=-\frac{1}{2018}-\frac{3}{2017^2}-\frac{5}{2017^3}-\frac{7}{2017^4};B=\frac{-1}{2018}-\frac{7}{2017^2}-\frac{5}{2017^3}-\frac{3}{2017^4}\)
So sánh A và B nếu
\(A=\frac{-1}{2018}-\frac{3}{2017^2}-\frac{5}{2017^3}-\frac{7}{2017^4}\)
\(B=\frac{-1}{2018}-\frac{7}{2017^2}-\frac{5}{2017^3}-\frac{3}{2017^4}\)
So sánh
\(A=\frac{2018^n-2017^n}{2018^n+2017^n}\)+\(\frac{2017^n-2016^n}{2017^n+2016^n}\)
Cho tổng A=\(\frac{2018}{2017^2+1}+\frac{2018}{2017^2+2}+\frac{2018}{2017^2+3}+...+\frac{2018}{2017^2+n}+...+\frac{2018}{2017^2+2017}\)
(A có 2017 số hạng). Chứng tỏ A không là số nguyên
So sánh: a)\(\frac{-3}{100}\)và \(\frac{2}{3}\) b)\(\frac{267}{-268}\)và\(\frac{-1347}{1343}\) c) \(\frac{2017\times2018-1}{2017\times2018}\)và\(\frac{2018\times2019-1}{2018\times2019}\) e)\(\frac{2017\times2018}{2017\times2018+1}\)và\(\frac{2018\times2019}{2018\times2019+1}\) Gải cách rút gọn cám ơn ạ
so sánh
a) \(\frac{2016}{2017}\)và\(\frac{2017}{2018}\)
b)\(\frac{2017}{2016}\)và\(\frac{2018}{2017}\)
\(\frac{2017}{1.2}+\frac{2017}{3.4}+\frac{2017}{4.5}+.....+\frac{2017}{99.100}=?\)
A = \(\frac{2016}{2017}+\frac{2017}{2018}+\frac{2018}{2019}\)và B = \(\frac{2016+2017+2018}{2017+2018+2019}\)