Các câu hỏi tương tự
so sanh I=5^0+..+5^9/5^0+5^9 va H= 3^0+...+3^8
so sanh
A=1+5+5^2+....++5^9 / 1+5+5^2+...+3^8 va B=1+3+3^2+...+3^9 / 1+3+3^2+...+3^8
so sanh A va B biet A=1+5+5^2+5^3+...+5^9/1+5+5^2+5^3+...+5^8 va B=1+3+3^2+3^3+...+3^9/1+3+3^2+3^3+...+3^8
so sánh
A=\(\frac{5^0+5^1+...+5^9}{5^0+5^1+...+5^8}\)
B=\(\frac{3^0+3^1+..+3^9}{3^0+3^1+...+3^8}\)
cho A:1+5+5^2+.....+5^9/1+5+5^2+.........+5^8
B:1+3+3^2+.....+3^9/1+3+3^2+.....3^8
so sanh A va B
Cho A=\(\frac{1+5+5^2+........+5^9}{1+5+5^2+........+5^8}\) va B=\(\frac{1+3+3^2+..........+3^9}{1+3+3^2+..........+3^8}\)
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So sanh A va B.
1-2-3-4-5-6-7-8-9-0+4+9+1+2+3+4+5:3:5:6:67:8:96+7+8+9+9-2-3-4-5-6-7-8-9-2+4+2+1+3+4+5+6+7+9+0+8+67?
LÂY BÚA CHAC ĐẦU ĐUÔI HỎI =?
1+3+5+7+....+(2x-1)=225
so sanh 9^200 va 27^133
2^180 va 8^61
2^101va 5^39
So sanh A va B, biet :
a)\(A=\frac{1+5+5^2+...+5^9}{1+5+5^2+...+5^8};B=\frac{1+3+3^2+...+3^9}{1+3+3^2+...+3^8}\)
b)\(A=\frac{7^{10}}{1+7+7^2+...+7^9};B=\frac{5^{10}}{1+5+5^2+...+5^9}\)