Ta có:
\(\frac{1234.1235-1}{1234.1235}=\frac{1234.1235}{1234.1235}-\frac{1}{1234.1235}=1-\frac{1}{1234.1235}\)
\(\frac{1235.1236-1}{1235.1236}=\frac{1235.1236}{1235.1236}-\frac{1}{1235.1236}=1-\frac{1}{1235.1236}\)
Vì 1/1234.1235 > 1/1235.1236
=> 1 - 1/1234.1235 < 1 - 1/1235.1236
Vậy .....
Ta có: \(\frac{1234.1235-1}{1234.1235}=\frac{1234.1235}{1234.1235}-\frac{1}{1234.1235}\)
= \(1-\frac{1}{1234.1235}\)
Lại có: \(\frac{1235.1236-1}{1235.1236}=\frac{1235.1236}{1235.1236}-\frac{1}{1235.1236}\)
= \(1-\frac{1}{1235.1236}\)
Vì 1234.1235 < 1235.1236 nên \(\frac{1}{1234.1235}>\frac{1}{1235.1236}\)
=> \(\frac{1234.1235-1}{1234.1235}>\frac{1235.1236-1}{1235.1236}\)