31/32= 1 -1/32
31317/32327= 1- 1010/32327
ta có 1010/32327 x 32 = 32320/32327 <1=32/32=1/32 x 32
=> 1010/32327<1/32 => 31317/32327 > 31/32
Ta có\(\frac{-31}{-32}=\frac{31}{32}=\frac{31310}{32320}\)
Vì 31310<32320 nên \(\frac{31310}{32320}< 1\)
\(\Rightarrow\frac{31310}{32320}< \frac{31310+7}{32320+7}=\frac{31317}{32327}\)
\(\frac{-31}{-32}< \frac{31317}{32327}\)
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