Ta có a/b >1 => a/b > a+n/b+n(a, b,n $\in$∈ N*)
B = 2010-1/2010-3 > 1 nên B = 2010-1/2010-3 > 2010-1+2/2010-3+2
= 2010+1/ 2010-1 = A
Vay \(A=\frac{2^{10}+1}{20^{10}-1}<\frac{20^{10}-1}{20^{10}-3}\)
So sánh A và B:
\(A=\frac{20^{10}+1}{20^{10}-1};B=\frac{20^{10}-1}{20^{10}-3}\)
So sánh A=\(\frac{20^{10}+1}{20^{10}-1}\)và B=\(\frac{20^{10}-1}{20^{10}-3}\)
So sánh : A=\(\frac{20^{10}+1}{20^{10}-1}\)và B=\(\frac{20^{10}-1}{20^{10}-3}\)
So sánh A và B
A = \(\frac{20^{10}+1}{20^{10}-1}\)Và B = \(\frac{20^{10}-1}{20^{10}-3}\)
So Sánh \(A=\frac{20^{10}+1}{20^{10}-1}\text{và }B=\frac{20^{10}-1}{20^{10}-3}\)
So sánh : \(A =\frac{20^{10} +1}{20^{10}-1} ; B =\frac{20^{10} -1}{20^{10} -3}\)
So sánh
A= \(\frac{20^{10}+1}{20^{10}-1}\) và B= \(\frac{20^{10}-1}{20^{10}-3}\)
so sánh \(A=\frac{20^{10}+1}{20^{10}-1};B=\frac{20^{10}-1}{20^{10}-3}\)
So sánh A và B:
a,A=\(\frac{10^{2004}+1}{10^{2005}+1}\)
B=\(\frac{10^{2005}+1}{10^{2006}+1}\)
b,A=\(\frac{20^{10}+1}{20^{10}-1}\)
B=\(\frac{20^{10}-1}{20^{10}-3}\)
So sánh \(A=\frac{20^{10}+1}{20^{10}-1}\)và\(B=\frac{20^{10}-1}{20^{10}-3}\)
