Ta có: B = (2018 + 2019)/(2019 + 2020) = (2018 + 2019)/4039 = 2018/4039 + 2019/4039
Ta thấy : 2018/2019 > 2018/4039
2019/2020 > 2019/4039
=> 2018/2019 + 2019/2020 > 2018/4039 > 2019/4039
=> 2018/2019 + 2019/2020 > (2018 + 2019)/(2019 + 2020)
=> A > B
SO SÁNH
A=2018^2019-1/2018^2019+1 VÀ B =2018^2019/2018^2019+2
So sánh hai phân số
A=2017/2018+2018/2019+2019/2020 và B=(2017+2018+2019)/(2018+2019+2020)
Cho A=\(\frac{2018^{2018}}{2019^{2019}}\) Và B=\(\frac{2018^{2018}+2018}{2019^{2019}+2019}\) So sánh A và B
So sánh A=2018^2019+1/2018^2019-2017 với B=2018^2019+2/2018^2019-2016
Giúp tớ giải vs tớ đag cần gấp❤❤❤❤
Bài toán : So sánh A và B
\(A=\frac{2018^{100}}{1+2018+2018^2+...+2018^{100}}\)
\(B=\frac{2019^{100}}{1+2019+2019^2+...+2019^{100}}\)
so sánh A=2017+2018 /2018+2019 và B=2017/2018+2018/2019
So sánh : A=20182019+1/20182019-2017
B=20182019+2/20182019-2016
so sánh A và B biết:
A=\(\dfrac{2^{2018}}{2^{2018}+3^{2019}}\)+\(\dfrac{3^{2019}}{3^{2019}+5^{2020}}\)+\(\dfrac{5^{2020}}{5^{2020}+2^{2018}}\)
B=\(\dfrac{1}{1.2}\)+\(\dfrac{1}{3.4}\)+\(\dfrac{1}{5.6}\)+...+\(\dfrac{1}{2019.2020}\).
A=2017+2018/2018+2019 và B = 2017/2018+2018/2019
So Sánh
