\(\text{So sánh : }\)
\(A=2017^{10}+2017^9=1,1149984e33\)
\(B=2018^{10}=1,11998349e33\)
\(\text{Vì : }1,1149984e33< 1,11998349e33\text{ nên }A< B\)
Ta có:
A=2017^10+2017^9
=2017^9.2017+2017^9
= 2017^9(2017+1)
=2017^9.2018
Lại có :
B=2018^10
=2018. 2018^9
So sánh : \(\hept{\begin{cases}2017< 2018=>2017^9< 2018^9\\2018=2018\end{cases}}\)
=> 2017^9.2018<2018^9.2018
Hay A<B
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