Question

So sánh A=2002^2,B=2001×2003

Answer 1

Có : A = 2002^2 = 2002.2002 =  (2001+1).(2002 = 2001.2002+2002 = (2001.2002+2001)+1 = 2001.(2002+1)+1 = 2001.2003+1>2001.2003

=> A > B 

k mk nha

Answer 2

Ta có : 

\(B=2001x2003=2001x\left(2001+2\right)=2001^2+4002\)

\(A=2002^2=\left(2001+1\right)^2=2001^2+4002+1=2001^2+4003\)

=> A>B 

Answer 3

Giải

A=2002^2

   =2002x2002=2002(2001+1)=2002x2001+2002x1=2002x2001+2002

B=2001x2003

   =2001x(2002+1)=2002x2001+2001x1=2002x2001+2001

Vì 2002>2001=>2002x2001+2002>2002x2001+2001=>A>B

Vậy.....