Ta có : \(A=\frac{1946}{1986};B=\frac{1968}{2008}\)
\(=>1-A=1-\frac{1946}{1986}=\frac{1986}{1986}-\frac{1946}{1986}=\frac{40}{1986}\)
\(=>1-B=1-\frac{1968}{2008}=\frac{2008}{2008}-\frac{1968}{2008}=\frac{40}{2008}\)
Vì \(\frac{40}{1986}>\frac{40}{2008}=>1-\frac{1946}{1986}>1-\frac{1968}{2008}\)
\(=>1-A>1-B\)
Từ đó suy ra : A < B