Question

so sanh a voi b biet;

a=75/100+78/21+19/32+22/21+13/32

b=(27,5x0,1+2,5x0,1)x2

Answer 1

ta có: \(A=\frac{75}{100}+\frac{78}{21}+\frac{19}{32}+\frac{22}{21}+\frac{13}{32}\)

\(A=\frac{3}{4}+\left(\frac{78}{21}+\frac{22}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)

\(A=\frac{3}{4}+4+\frac{16}{21}+1\)

\(A=5+\frac{3}{4}+\frac{16}{21}\)

\(B=\left(27,5\times0,1+2,5\times0,1\right)\times2\)

\(B=\left[\left(27,5+2,5\right)\times0,1\right]\times2\)

\(B=\left(30\times0,1\right)\times2\)

\(B=5\)

\(\Rightarrow5+\frac{3}{4}+\frac{16}{21}>5\)

\(\Rightarrow A>B\)