A = 1998.2002 = 1998.(2000+2) = 1998.2000 + 1998.2
B = 2000.2000 = (1998+2).2000 = 1998.2000 + 2.2000
Vì 1998 < 2000
=> 2.1998 < 2.2000
=> 1998.2000 + 1998.2 < 1998.2000 + 2000.2
=> A < B
Ta có :
\(A=1998.2002=\left(2000-2\right).\left(2000+2\right)=2000.\left(2000+2\right)-2.\left(2000+2\right)=2000^2-2.2\)\(B=2000.2000=2000^2\)
Vậy A < B