Ta thấy:A=\(\frac{10^{19}+1}{10^{20}+1}\)=>10A=\(\frac{10^{20}+10}{10^{20}+1}\)
=>10A=\(\frac{10^{20}+1+9}{10^{20}+1}\)
=>10A=1+\(\frac{9}{10^{20}+1}\)
Ta thấy:B=\(\frac{10^{20}+1}{10^{21}+1}\)
=>10B=\(\frac{10^{21}+10}{10^{21}+1}\)
=>10B=\(\frac{10^{21}+1+9}{10^{21}+1}\)
=>10B=1+\(\frac{9}{10^{21}+1}\)
Do \(\frac{9}{10^{20}+1}\)> \(\frac{9}{10^{21}+1}\)=>A > B
A>B or A<B; A=B if A = \(\frac{10^{19}+1}{10^{20}+1}\) and B = \(\frac{10^{20}+1}{10^{21}+1}\) ?
Cho a,b,c > 0. CMR \(\frac{a}{b}< \frac{a+c}{b+c}\). Áp dụng so sánh \(A=\frac{10^{17}+1}{10^{16}+1}\)Và \(B=\frac{10^{16}+1}{10^{15}+1}\)
cho \(\frac{x^4}{a}\)+\(\frac{y^4}{b}\)=\(\frac{1}{a+b}\)và \(x^2\)+\(y^2\)=1
CMR: \(\frac{x^{20}}{a^{10}}\)+\(\frac{y^{20}}{b^{10}}\)=\(\frac{2}{\left(a+b\right)^{10}}\)
Help me do my homewok !
\(\frac{10^{10}+1}{10^{11}+1}\)và \(\frac{10^{11}-1}{10^{12}-1}\)
So sánh
Can you help me ?
Rút gọn M=\(\frac{a^{30}+a^{20}+a^{10}+1}{a^{2042}+a^{2032}+a^{2022}+a^{2012}+a^{30}+a^{20}+a^{10}+1}\)
1.so tu nhien x thoa man 2.3x+3x+2=99
2. gia tri a de da thuc 6x2-ax-5 chia het cho 3x-5
3.\(\frac{10^{19}.7^{21}}{49.14^{18}.5^{20}}+\frac{15^{31}.32^5}{6^{24}.3^7.5^{30}}=?\)
Tìm x,y biết:
a/\(x^2+\left(y-\frac{1}{10}\right)=0\)
b/\(\left(\frac{1}{2}x-5\right)^{20}+\left(y^2-\frac{1}{4}\right)10\le0\)
\(1\frac{1}{2}+2\frac{1}{6}+3\frac{1}{12}+4\frac{1}{20}+5\frac{1}{30}+6\frac{1}{42}+7\frac{1}{56}+8\frac{1}{72}+9\frac{1}{90}+\frac{1}{10}\)\(\frac{1}{10}=?\)
bài 1 tính \(\frac{10^{19}.7^{21}}{49.14^{18}.5^{20}}+\frac{15^{31}.32^5}{6^{24}.3.5^{30}}\)
bài 2) giá trị của x lớn hơn 0
lx-9l+(-l2-xl)=0
