a)2300=(23)100=8100
3200=(32)100=9100
vì 8<9 nên 8100<9100
hay 2300<3200
b)212=24.3=(24)3=163
418=42.9=(42)9=169
\(2^{300}=\left(2^3\right)^{100}=8^{100}\)
\(3^{200}=\left(3^2\right)^{100}=9^{100}\)
=> \(3^{200}>2^{300}\)
\(2^{12}=\left(2^4\right)^3=16^3\)
\(4^{18}=\left(4^2\right)^9=16^9\)