B=2000/2001+2002 + 2001/2001+2002
Ta có:2000/2001 > 2000/2001+2002
2001/2002 > 2001/2001+2002
Vậy A >B
Ta có:
B = \(\frac {2000+2001}{2001+2002}\)
= \(\frac {2000}{2001+2002} + \frac {2001}{2001+2002}\)
Vì \(\frac {2000}{2001} > \frac {2000}{2001+2002}\)
Mà \(\frac {2001}{2002} > \frac {2001}{2001+2002}\)
=> \(\frac {2000}{2001} + \frac {2001}{2002} > \frac {2000+2001}{2001+2002}\)
=> A > B.