chung minh rang :
\(\frac{1}{4}\)+\(\frac{1}{16}\)+\(\frac{1}{36}\)+\(\frac{1}{64}\)+\(\frac{1}{100}\)+\(\frac{1}{144}\)+\(\frac{1}{196}\)<\(\frac{1}{2}\)
Cho A= 1/4+1/6+1/46+1/64+1/144+/196
C.m A>1/2
cho a=(1-1/2)*(1-1/3)*(1-1/4)*...(1-1/19)*(1-1/20)
b=(1-1/4)*(1-1/9)*(1-1/16)*...*(1-1/18)*(1-1/180)
so sanh a va 1/21
so sanh b va 11/21
so sanh M va N, biet:
N=364
M=2(3+1)(32+1)(33+1)(316+1)(332+1)
so sanh A= 1/2^2 + 1/3^2 + ....... + 1/100^2 va B= 1/4^2 + 1/6^2 +.... +1/200^2
so sanh (1/16)^200 va 1/2^1000
Cho M=(1\4-1)×(1\9-1)×(1\16-1)×...×(1\81-1)×(1\100-1)
So sanh M voi -11\21
SO SÁNH:
a,1015+1/1016+1 va 1016+1/1017+1
b,A=1/22+1/32+1/42+...+1/1002 va B=3/4
c,A=1+1/2+...+1/100 va B=5/4
GIẢI GIÚP MÌNH NHÉ
so sanh A va B
A = 100^101 + 1 / 100^100 + 1
B = 100^100 + 1 / 100^99 + 1