đặt A = 1/1.2+1/2.3+...+1/49.50
Ta có :
A= 1/1.2+1/2.3+...+1/49.50
=1-1/2+1/2-1/3+...+1/49-1/50
=1-1/50 < 1
=> A < 1
đặt A = 1/1.2+1/2.3+...+1/49.50
Ta có :
A= 1/1.2+1/2.3+...+1/49.50
=1-1/2+1/2-1/3+...+1/49-1/50
=1-1/50 < 1
=> A < 1
đặt A = 1/1.2+1/2.3+...+1/49.50
Ta có :
A= 1/1.2+1/2.3+...+1/49.50
=1-1/2+1/2-1/3+...+1/49-1/50
=1-1/50 < 1
=> A < 1