\(\frac{10^{50}+1}{10^{50}-3}=\frac{\left(10^{50}-3\right)+4}{10^{50}-3}=1+\frac{4}{10^{50}-3}\)
\(\frac{10^{50}+3}{10^{50}-1}=\frac{\left(10^{50}-1\right)+4}{10^{50}-1}=1+\frac{4}{10^{50}-1}\)
Ta so sánh \(\frac{4}{10^{50}-3}với\frac{4}{10^{50}-1}\) . Ta có \(\frac{4}{10^{50}-3}\) > \(\frac{4}{10^{50}-1}\) => 1050+1/1050-3 > 1050+3/1050-1
Ta có :
\(\frac{10^{50}+1}{10^{50}-3}=\frac{10^{50}-3+4}{10^{50}-3}=1+\frac{4}{10^{50}-3}\)
\(\frac{10^{50}+3}{10^{50}-1}=\frac{10^{50}-1+4}{10^{50}-1}=1+\frac{4}{10^{50}-1}\)
Do \(\frac{4}{10^{50}-3}>\frac{4}{10^{50}-1}\)
\(\Rightarrow1+\frac{4}{10^{50}-3}>1+\frac{4}{10^{50}-1}\)
\(\Rightarrow\frac{10^{50}+1}{10^{50}-3}>\frac{10^{50}+3}{10^{50}-1}\)
Chúc bạn học tốt !!!
10 mũ 50 +1:10 mũ 50-3 = 10 mũ 50 -1
10 mũ 50 + 1 : 10 mũ 50-3 = 10 mũ 50 -1
thank you nhiều mình lấy nick khác k cho nha
Đặt A=\(\frac{10^{50}+1}{10^{50}-3}=\frac{10^{50}-3+4}{10^{50}-3}=1+\)\(\frac{4}{10^{50}-3}\)(1)
\(B=\frac{10^{50}+3}{10^{50}-1}=\frac{10^{50}-1+4}{10^{50}-1}=1+\frac{4}{10^{50}-1}\left(2\right)\)
So sánh ta thấy \(\frac{4}{10^{50}-3}\)< \(\frac{4}{10^{50}-1}\)
=> (1)<(2)
=> A<B
tk mk nha bn
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