Ta có:\(\sqrt{3}-1=-1+\sqrt{3}< -1+\sqrt{4}=-1+2=1\)
\(\Rightarrow\sqrt{3}-1< 1\)
\(\sqrt{3-1}\)=\(-1+\sqrt{3}\)
Vậy \(1>\sqrt{3-1}\)
Tuyển Cộng tác viên Hoc24 nhiệm kì 28 tại đây: https://forms.gle/GrfwFgzveoKLVv3p6
Ta có:\(\sqrt{3}-1=-1+\sqrt{3}< -1+\sqrt{4}=-1+2=1\)
\(\Rightarrow\sqrt{3}-1< 1\)
\(\sqrt{3-1}\)=\(-1+\sqrt{3}\)
Vậy \(1>\sqrt{3-1}\)
so sanh : A=\(\sqrt{11+\sqrt{96}}\) va B=\(\frac{2\sqrt{2}}{1+\sqrt{2}-\sqrt{3}}\)
1`)So Sanh
a)\(\sqrt{24}+\sqrt{45}\) va 12
b)\(\sqrt{37}-\sqrt{15}\)va 2
giup mk voi nhe
So sanh \(A=\sqrt[1995]{1996!}\) va \(B=1+\sqrt[1995]{1995!}\)
so sanh 3+\(2\sqrt{2}\)va 7-\(\sqrt{3}\)
\(\sqrt{24}+\sqrt{63}+3\)va 16 .so sanh
so sanh \(-3\sqrt{7}\)va \(-9\)
so sanh :\(\sqrt{1999}+\sqrt{2001}..va..2\sqrt{2000}\)
So sanh: x=\(\sqrt{2019}\)va y=\(2\sqrt{2018}-\sqrt{2017}\)
so sanh 10\(\sqrt{51}\)va 70+\(\sqrt{2}\)