Ta có : x5 = x12
=> x5 - x12 = 0
x5 ( 1 - x7 ) = 0
=> x5 = 0 hoặc 1 - x7 = 0
+ Nếu x5 = 0 => x = 0
+ Nếu 1 - x7 = 0
=> x7 = 1 = 17
=> x = 1
Vậy : x thuộc { 0 ; 1 }
so nguyen duong x thoa man X5=x12
tim cac so nguyen duong x,y thoa man 2x+3y=14
cap so nguyen duong x;y thoa man |(x2+2).(y+1)| =9
so nguyen duong X thoa man 49-l-17-(-15)-Xl=-3+27
tim cac so nguyen duong x,y,z thoa man x^2+y^3+z^4
Tim so nguyen duong x,y thoa man dang thuc
x2+xy-2=0
cho x va y la so nguyen duong nho hon 10 ,thoa man 3x-4y=-21
cho cac so nguyen duong a,b,x,y thoa man a+b=x+y;ab+a=xy.cmr:x=y
cho x la so nguyen thoa man : -7/25<x/30<-1/5. so gia tri cua x thoa man la
