S=\(\frac{3}{1.4}\)+\(\frac{3}{4.7}\)+...+\(\frac{3}{40.43}\)+\(\frac{3}{43.46}\)
3S=\(\frac{9}{1.4}\)+\(\frac{9}{4.7}\)+...+\(\frac{9}{40.43}\)+\(\frac{9}{43.46}\)
3S=9-\(\frac{9}{4}\)+\(\frac{9}{4}\)-\(\frac{9}{7}\)+...+\(\frac{9}{40}\)-\(\frac{9}{43}\)+\(\frac{9}{43}\)-\(\frac{9}{46}\)
3S=9-\(\frac{9}{46}\)
3S=\(\frac{405}{46}\)
S=\(\frac{405}{46}\):3
S=\(\frac{135}{46}\)
=> S>1 mới đúng
S=3/1.4+3/4.7+3/7.10+...+3/40.43+43.46 CHứng minh S<1
Cho S=3/1.4+3/4.7+3/7.10+...+3/40.43+3/32+46 .Hay chung to rang S<1
cho S= 3/1.4+3/4.7+3/7.10+....+3/40.43+3/43. 46
chứng tở rằng S<1
Cho S=3/1.4+3/4.7+3/7.10+...+3/40.43+3/43.46 . Chứng tỏ rằng S<1
cho S= \(\dfrac{3}{1.4}+\dfrac{3}{4.7}+\dfrac{3}{7.10}+...+\dfrac{3}{40.43}+\dfrac{3}{43.46}\)
Hãy chứng tỏ rằng S<1
CHO S : 3/1.4 + 3/4.7 + 3/7.10 ... + 3/40.43 + 3/43.46
HÃY CHỨNG TỎ RẰNG S <1
Cho S= 3/1.4+3/4.7+3/7.10+.......3/40.43+3/43.46.
Hãy chứng tỏ rằng S<1
Cho S=\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+.....+\frac{3}{40.43}+\frac{3}{43.46}\)
Hãy chứng minh S <1
S=3/1.4 +3/4.7 +3/7.10 +...+3/40.43 +3/43.46
