S = 1 x 2 x 3 x 4 + 2 x 3 x 4 x 5 + ... + 2015 x 2016 x 2017 x 2018
\(\frac{x+4}{2015}+\frac{x+3}{2016}=\frac{x+2}{2017}+\frac{x+1}{2018}\text{ }\text{ }\)
\(\frac{x-1}{2018}+\frac{x-2}{2017}-\frac{x-3}{2016}=\frac{x-4}{2015}\)
Tìm x
2/5×(x-1)+1=3/5
(2/7×x+1)×(3-1/2×x)=0
5/4×x+1=1/2x+3/4
X-2020/10^2+x-202^0/10^3+x-2020/10^4=0
0x+1/2018+x+2/2017=x+3/2016-x+4/2015
2015
Nhanh tk nha
a, x+1/2013+x+1/2014+x+1/2015=x+1/2016+x+1/2017
b,x-1/2013+x-2/2014+x-3/2015=x-4/2016-2
(1+1/2+1/3+........+1/205)*x+2015=2016/1+2017/2+2018/3+......+4030/2015
tìm x
Tìm x biết
a)x/2+x/3+x/4+x/5=0
b)x+1/2019 + x+2/2018 = x+3/2017 + x+4/2016
cho \(x,y\ne0\)thỏa mãn\(x^{2015}+x^{2015}=x^{2016}+x^{2016}=x^{2017}+x^{2017}\)
tính \(S=2018.\left(x^{2018}+y^{2018}\right)\)
tim x
x + 4 / 2018 + x+ 5 / 2017 + x + 6 / 2016 + x+ 7 / 2015 = - 4