a)\(\frac{2.5.13}{2.13.5.7}=\frac{1}{7}\)
\(\frac{2^3.3^3.7.5}{2^3.3^3.7.2}=\frac{5}{2}\)
f. =\(\frac{4\cdot7}{9\cdot4\cdot8}=\frac{7}{8\cdot9}=\frac{7}{72}\)
c.\(\frac{17\cdot5-17}{3-20}=\frac{17\cdot\left(5-1\right)}{-17}=\frac{17\cdot4}{-17}=-4\)
d. Ạ=\(\frac{294\cdot14-14}{294\cdot35-15}=\frac{14\cdot\left(294-1\right)}{35\cdot\left(294-1\right)}=\frac{14}{35}=\frac{2}{5}\)
e. B=\(\frac{101\cdot29-101}{3838+404}=\frac{101\cdot\left(29-1\right)}{202\cdot19+202\cdot2}=\frac{101\cdot28}{202\cdot\left(19+2\right)}=\frac{101\cdot4\cdot7}{202\cdot3\cdot7}=\frac{1}{2}\cdot\frac{4}{3}=\frac{2}{3}\)
N=\(\frac{-5}{7}\cdot\left(\frac{2}{11}+\frac{9}{11}\right)+1\frac{5}{7}=\frac{-5}{7}\cdot1+1+\frac{5}{7}=\left(\frac{-5}{7}+\frac{5}{7}\right)+1=1\)