Các câu hỏi tương tự
CTR:A=\(\frac{1}{26}+\frac{1}{27}+...+\frac{1}{49}+\frac{1}{50}=\frac{99}{50}-\frac{97}{49}+...+\frac{7}{4}-\frac{5}{3}+\frac{3}{2}-1\)
Tìm x, biết :
a, \(60\%x+0,4x+x:3=2\)
b, \(\left|2x-5\right|-7=\left(\frac{1}{49}-\frac{1}{3^2}\right)\left(\frac{1}{49}-\frac{1}{4^2}\right)...\left(\frac{1}{49}-\frac{1}{2015^2}\right)\)
c, \(\frac{x+1}{1}+\frac{2x+3}{3}+\frac{3x+5}{5}+...+\frac{20x+39}{39}=22+\frac{4}{3}+\frac{6}{5}+...+\frac{40}{39}\)
rut gon bieu thuc sau
a . S=1+\(\frac{1}{3}+\frac{1}{^{^{3^2}}}+\frac{1}{3^3}+...+\frac{1}{3^n}\)
Tìm \(x\) biết:
a)\(\left|2x-5\right|-7=\left(\frac{1}{49}-\frac{1}{3^2}\right)\left(\frac{1}{49}-\frac{1}{4^2}\right).....\left(\frac{1}{49}-\frac{1}{2015^2}\right)\)
b)\(\frac{x+1}{1}+\frac{2x+3}{3}+\frac{3x+5}{5}+...+\frac{20x+39}{39}=22+\frac{4}{3}+\frac{6}{5}+...+\frac{40}{39}\)
Chứng minh rằng:\(\frac{1}{26}+\frac{1}{27}+\frac{1}{28}+....+\frac{1}{49}+\frac{1}{50}=\frac{91}{50}-\frac{97}{49}+\frac{95}{48}-\frac{93}{47}+.....+\frac{7}{4}-\frac{5}{3}+\frac{3}{2}=1\)
Tìm x : \(\frac{6:\frac{3}{5}-1\frac{1}{16}\cdot\frac{6}{7}}{4\frac{1}{5}\cdot\frac{10}{11}+5\frac{2}{11}}\)\(-\frac{\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{5}\right)\cdot\frac{12}{49}}{3\frac{1}{3}+\frac{2}{9}}\)
Tìm x biết :
\(\left[\frac{6:\frac{3}{5}-1\frac{1}{16}.\frac{6}{7}}{4\frac{1}{5}.\frac{10}{11}+5\frac{2}{11}}-\frac{\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{15}\right).\frac{12}{49}}{3\frac{1}{3}+\frac{2}{9}}\right].x=2\frac{23}{96}\)
TÍNH HỢP LÍa)frac{frac{4}{17}-frac{4}{49}-frac{4}{131}}{frac{-3}{17}+frac{3}{49}+frac{3}{131}}b)frac{-1}{2}+frac{3}{5}+frac{-1}{9}+frac{1}{27}+frac{7}{18}+frac{4}{35}+frac{2}{7}c)frac{3.8.15....9999}{4.9.16.....10000}d)frac{frac{1}{2}+frac{1}{3}+frac{1}{4}+...+frac{1}{2000}}{frac{1999}{1}+frac{1998}{2}+frac{1997}{3}+...+frac{1}{1999}}
Đọc tiếp
TÍNH HỢP LÍ
a)\(\frac{\frac{4}{17}-\frac{4}{49}-\frac{4}{131}}{\frac{-3}{17}+\frac{3}{49}+\frac{3}{131}}\)
b)\(\frac{-1}{2}+\frac{3}{5}+\frac{-1}{9}+\frac{1}{27}+\frac{7}{18}+\frac{4}{35}+\frac{2}{7}\)
c)\(\frac{3.8.15....9999}{4.9.16.....10000}\)
d)\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2000}}{\frac{1999}{1}+\frac{1998}{2}+\frac{1997}{3}+...+\frac{1}{1999}}\)
Tính A = \(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{49}+\frac{1}{50}}{\frac{1}{49}+\frac{2}{48}+\frac{3}{47}+...+\frac{48}{2}+\frac{49}{1}}\)