Question

Rút gọn:

a/ \(\frac{4\cdot7}{9\cdot32}\)

b/ \(\frac{3\cdot21}{14\cdot15}\)

c/ \(\frac{2\cdot5\cdot13}{26\cdot35}\)

d/ \(\frac{9\cdot6-9\cdot3}{18}\)

e/ \(\frac{17\cdot5-17}{3-20}\)

f/ \(\frac{49+7\cdot49}{49}\)

Answer 1

a,\(\frac{4.7}{9.32}=\frac{7}{9.8}=\frac{7}{72}\)

Answer 2

a) \(\frac{4.7}{9.32}\)=\(\frac{28}{288}\)=\(\frac{7}{72}\)

b)\(\frac{3.21}{14.15}\)=\(\frac{63}{210}\)=\(\frac{3}{10}\)

c)\(\frac{2.5.13}{26.35}\)=\(\frac{130}{910}\)=\(\frac{1}{7}\)

d)\(\frac{9.6-9.3}{18}\)=\(\frac{27}{18}\)=\(\frac{3}{2}\)

e)\(\frac{17.5-17}{3-20}\)=\(\frac{68}{-17}\)=\(-4\)

f)\(\frac{49+7.49}{49}\)=\(\frac{392}{49}\)=\(8\)

Answer 3

\(a,\frac{4.7}{9.32}=\frac{4.7}{9.4.8}=\frac{7}{9.8}=\frac{7}{72}\)

\(b,\frac{3.21}{14.15}=\frac{3.3.7}{2.7.3.5}=\frac{3}{2.5}=\frac{3}{10}\)

\(c,\frac{2.5.13}{26.35}=\frac{2.5.13}{13.2.5.7}=\frac{1}{7}\)

\(d,\frac{9.6-9.3}{18}=\frac{9.\left(6-3\right)}{18}=\frac{9.3}{18}=\frac{9.3}{2.9}=\frac{3}{2}\)

\(e,\)\(\frac{17.5-17}{3-20}=\frac{17.\left(5-1\right)}{-17}=\frac{17.4}{-17}=\frac{-17.\left(-4\right)}{-17}=-4\)

\(f,\frac{49+7.49}{49}=\frac{49.\left(1+7\right)}{49}=\frac{49.8}{49}=8\)