Question

Rut gon tong sau

C=1+2^2+2^4+....+2^2008

Pn nao chỉ mk dau tien mk tick cho phai trong toi nay nhe

Answer 1

\(C=1+2^2+2^4+...+2^{2008}\)

\(\Rightarrow4C=2^2+2^4+...+2^{2010}\)

\(\Rightarrow4C-C=\left(2^2+2^4+...+2^{2010}\right)-\left(1+2^2+2^4+...+2^{2008}\right)\)

\(3C=2^{2010}-1\)

\(C=\frac{2^{2010}-1}{3}\)

Answer 2

\(C=1+2^2+2^4+....+2^{2008}\)

\(\Rightarrow4C=2^2+2^4+.....+2^{2010}\)

\(\Rightarrow3C=4C-C=\left(2^2+2^4+...+2^{2010}\right)-\left(1+2^2+.....+2^{2008}\right)\)

\(\Rightarrow3C=2^{2010}-1\)

\(\Rightarrow C=\frac{2^{2010}-1}{3}\)

Answer 3

C=1+22+24+...+22008

⇒4C=22+24+...+22010

⇒4C−C=(22+24+...+22010)−(1+22+24+...+22008)

3C=22010−1

C=22010−13 

Answer 4

\(C=1+2^2+2^4+...+2^{2008}\)

\(\Rightarrow4C=2^2+2^4+...+2^{2010}\)

\(\Rightarrow4C-C=\left(2^2+2^4+...+2^{2010}\right)-\left(1+2^2+2^4+...+2^{2008}\right)\)

\(3C=2^{2010}-1\)

\(C=\frac{2^{2010}-1}{3}\)