\(\frac{3}{15}-\frac{5}{35}=\frac{1}{5}-\frac{1}{7}=\frac{7}{35}-\frac{5}{35}=\frac{2}{35}\)
Ta có:\(\frac{3}{15}-\frac{5}{35}\)
=\(\frac{1}{5}-\frac{1}{7}\)
=\(\frac{7}{35}-\frac{5}{35}\)
=\(\frac{7-5}{35}\)
=\(\frac{2}{35}\)
\(\frac{3}{15}-\frac{5}{35}=\frac{105}{525}-\frac{75}{525}=\frac{105-75}{525}=\frac{30}{525}=\frac{2}{35}\)