Ta có: +) \(\frac{7.12^3+2.12^3}{4^4.3^5}=\frac{12^3.\left(7+2\right)}{\left(2^2\right)^4.3^5}=\frac{\left(2^2.3\right)^3.\left(3^2\right)}{2^8.3^5}=\frac{2^6.3^3.3^2}{2^8.3^5}=\frac{2^6.3^5}{2^8.3^5}=\frac{1}{2^2}=\frac{1}{4}\)
+)\(\frac{-17.10+17.6}{18.11+18.6}=\frac{17.\left(-10\right)+17.6}{18.11+18.6}=\frac{17.\left(-10+6\right)}{18.\left(11+6\right)}=\frac{17.\left(-4\right)}{18.17}=\frac{-4}{18}=\frac{-2}{9}\)
+)\(\frac{6.7.8.9}{4.12.14.13}=\frac{2.3.7.2^3.3^2}{2^2.2^2.3.2^2.7.13}=\frac{2^4.7.3^3}{2^6.3.7.13}=\frac{3^2}{2^2.13}=\frac{9}{4.13}=\frac{9}{52}\)
Ta lại có: \(\frac{1}{4}=\frac{117}{468};\frac{-2}{9}=\frac{-104}{468};\frac{9}{52}=\frac{81}{468}\)
