Question

Rút gọn phân số:

a,\(\frac{4545+101}{6969-303}\)

b,\(\frac{2929-101}{2.1919+404}\)

Làm giúp mk bài này nha!Cảm ơn mn nhiều:3

Answer 1

Bài giải

a) Ta có : \(\frac{4545+101}{6969-303}=\frac{45.101+101}{69.101-101.3}=\frac{101.\left(45+1\right)}{101.\left(69-3\right)}=\frac{101.46}{101.66}=\frac{23}{33}\)

b) Ta có : \(\frac{2929-101}{2.1919+404}=\frac{29.101-101}{2.19.101+4.101}=\frac{101.\left(29-1\right)}{101.\left(19.2+4\right)}=\frac{28}{42}=\frac{2}{3}\)

Answer 2

a)\(\frac{4545+101}{6969-303}\)= \(\frac{\left(4545:45\right)+101}{\left(6969:69\right)-303}\)= \(\frac{101+101}{101-303}\)=\(\frac{202}{-202}\)=-1 

b)\(\frac{2929-101}{2.1919+404}\)= \(\frac{2929-101}{3838+404}\)=\(\frac{\left(2929:29\right)-101}{\left(3838:38\right)+404}\)=\(\frac{101-101}{101+404}\)=\(\frac{0}{505}\)=0

học tốt 

Answer 3

a)\(\frac{4545+101}{6969-303}=\frac{\left(4545:45\right)+101}{\left(6969:69\right)-303}=\frac{101+101}{101-303}=\frac{202}{-202}=-1\)

b)\(\frac{2929-101}{2.1919+404}=\frac{2929-101}{3838+404}=\frac{\left(2929:29\right)-101}{\left(3838:38\right)+404}=\frac{101-101}{101+404}=0\)

Học tốt

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Answer 4

a ) \(\frac{4545+101}{6969-303}\)

\(=\frac{45\times101+101}{69\times101-101\times3}\)

\(=\frac{101\times\left(45+1\right)}{101\times\left(69-3\right)}\)

\(=\frac{101\times46}{101\times66}\)

\(=\frac{23}{33}\)

b ) \(\frac{2929-101}{2\times1919+404}\)

\(=\frac{29\times101-101}{2\times19\times101+4\times101}\)

\(=\frac{101\times\left(29-1\right)}{101\times\left(19\times2+4\right)}\)

\(=\frac{28}{42}=\frac{2}{3}\)