a/ \(\frac{\left(x+2\right)\left(x+6\right)}{x+2}\) = X + 6
b/\(\frac{3a+3b+3c}{a+b+c}\) = \(\frac{3\left(a+b+c\right)}{a+b+c}\)= 3
c/\(\frac{\left(2a+b\right)c+c\left(b-a\right)}{\left(a+b\right)c}\)= \(\frac{c\left(2a+b+b-a\right)}{\left(a+b\right)c}\)= \(\frac{c\left(a+2b\right)}{\left(a+b\right)c}\)= \(\frac{a+2b}{a+b}\)
Cám ơn bạn nhìu nha, mik ngồi đợi mãi câu trả lời đây, thanks you bạn nhìu