Viết lại cái đề cho rõ:
\(\frac{121.75.130.169}{39.60.11.198}=\frac{11.11.15.5.13.10.13.13}{13.3.15.4.11.11.18}=\frac{5.10.13.13}{3.4.18}=\frac{5.2.5.13.13}{3.2.2.18}=\frac{5.5.13.13}{3.2.18}=\frac{4225}{108}\)
tong cua tu so va mau so cua mot phan so la 4812 sau khi rut gon phan so do ta duoc phan so 5/7 hay tim phan so chua rut gon
Khong dung may tinh bo tui .Rut gon roi quy dong cac phan so sau
a)\(\frac{17}{20},\frac{13}{15}va\frac{41}{60}\)
b)\(\frac{25}{75},\frac{17}{34}va\frac{121}{132}\)
tìm phân số biết tong cua tu va mau la 25 va khi rut gon thi duoc phan so -2/3
hieu vua mau va tu la 140 va khi rut gon phan so do thi duoc phan so 2/3
hieu cua tu va mau la 9 .dong thoi sau khi rut gon phan so do la 5/2 . tim phan so do
Mot phan so co tong cua tu va mau la 190. Sau khi rut gon thi diocese 5/33. Hay tim phan so do
mau cua mot phan so lon hon tu 14 don vi sau khi rut gon ta duoc phan so 993/1000.hay tim phan so ban dau
Cho cac so nguyen duong a,b,c,x,y,z
1, Biet 1/a = 3/b + c = 5/c + a. Hay rut gon phan so A = a/2b - c
2. Biet a/b = 2b/cc = 4c/a. Hay rut gon phan so B = ab + bc + ca/a2 + b + c2
3. Biet x/a = y/b =z/c. Hay rut gon phan so C = x*y*z*(b+c)*(c+a)*(a+b)/a*b*c(y+z)*(z+x)*(x+y)
4. Biet ab/a + 2b = 2/5; bc/b + 2c = 3/4; ca/c +2a = 3/5. Hay rut gon phan so D = abc/ab+bc+ca
5. Biet 3/a -4b = 5c. Hay rut gon phan so E = 3bc + ab - 4ac/6bc - 8ac -ab
Giup minh nhe! Ai lam duoc va dung cho tick.
Thanks cac ban
Cho cac so nguyen duong a,b,c,x,y,z
1, Biet 1/a = 3/b + c = 5/c + a. Hay rut gon phan so A = a/2b - c
2. Biet a/b = 2b/cc = 4c/a. Hay rut gon phan so B = ab + bc + ca/a2 + b + c2
3. Biet x/a = y/b =z/c. Hay rut gon phan so C = x*y*z*(b+c)*(c+a)*(a+b)/a*b*c(y+z)*(z+x)*(x+y)
4. Biet ab/a + 2b = 2/5; bc/b + 2c = 3/4; ca/c +2a = 3/5. Hay rut gon phan so D = abc/ab+bc+ca
5. Biet 3/a -4b = 5c. Hay rut gon phan so E = 3bc + ab - 4ac/6bc - 8ac -ab
Giup minh nhe! Ai lam duoc va dung cho tick.
Thanks cac ban
rut gon phan so sau
\(\frac{3.13-13.18}{15.40-80}\)
